Japanese crossword #26536
| Size: 30x25 | Picture: | Difficulty: | Added: | 03.09.19 | Author: Yvan |
0:00:00
| ||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||||
|
COMMENTS
Ah that's so cute!
Wonderful! The asymmetry adds so much interest and challenge!
Спасибо за прекрасный кроссворд!
Спасибо за прекрасный кроссворд!
For people solving this in ~15-30 minutes: can you tell me how you did it? I'm pretty new to nonograms, but it ook me 1 hour and 5 minutes. I should add though that I do not "cheat" in any form or way. Even though it was obvious mid way through the nonogram there was a lot of symmetry, I did not abuse that idea to solve it.
show: 2 🗨
don't know if this is a trick you already know, but i'll share.
If you want to know on a long line if there are any "sure" squares, add up the numbers you have on the line/columns, +1 for every space, and see if the space remaining is lower than any of those numbers. If it is, those are the numbers of squares that can be blackened out.
Quick and easy example: you line/column has 11 cells, and you need to fill it with 3,3,1. Your math is 3+3+1+2(for blank spaces)=9. 11-9=2. This means that every number greater than 2 can be blackened out, by the difference with 2 (3-2=1 sure cell on every 3 string).
If you want to know on a long line if there are any "sure" squares, add up the numbers you have on the line/columns, +1 for every space, and see if the space remaining is lower than any of those numbers. If it is, those are the numbers of squares that can be blackened out.
Quick and easy example: you line/column has 11 cells, and you need to fill it with 3,3,1. Your math is 3+3+1+2(for blank spaces)=9. 11-9=2. This means that every number greater than 2 can be blackened out, by the difference with 2 (3-2=1 sure cell on every 3 string).
show: 1 🗨
show: 1 🗨